NECO 2017 mathematics obj & theory answer available @askloaded3

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==>

/ means division or divide

Log means logarithm

* means multiplication

^ means Raise to power

Tita means θ

Pie means π

Base means subscript

Sqr root means √

bar means a dash on top a number of letter

—(1) means equation 1

Proportional means ∝

Verified-Maths-Obj
1CDAAEDEECE
11EEBABAABCC
21BBCEDABECD
31BCCCDDCADE
41BDCBDCCECD
51BCDCBEDCDB

VERIFIED

(1)

tabulate:

Number-

5932

*6141

num

3679

*3113

den

Log

3.7732

3.7882

7.5612

3.5657

3.4931

7.0588

anti log

7.5612

7.0588/0.5024/3=0.1675

anti log

=1471*10

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(2)

a = 3, b = 20, C = -7

Sum is

(α/1 + 1/β + β/1 + 1/ α) Note α means Alpha

α^2 β + β^2 + α + β / α β

= -7/3 (-20/3) + (-20/3) = 140/9 – 20/3 / -7/3

(please Note / means Divided)

= 80/9 x -3/7 = -80/21

Product:

-7/3 + 2 + 1/-7/3 = -7/3 + 2/1 – 3/7

= -49+42-9/21

= -16/21

x^2 – (sum)x + product= 0

x^2 – 80/21x + (-16/21) = 0

Final Answer : 21x^2 – 80x – 16 = 0

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(3a)
P=100I/RT=100*30,000/4*3
P=N250,000

(3b)
#7000 T0 FRANCS
8FRANS= #1
?FRANCS =7000
CROSS MULTIPLY
=#56,000 FRANCS
SPENDING 49,400 FRANCS
56,000-49,400 = 6600
CONVERTING 6,600 FRANCS TO # AT 10 FRANCS TO 1#
10 FRANCS—– 1#
6600 FRANCS—?#
=6,600/10 X1
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(4i)
difference in latitude=36degree + 36 degree =72degree
distance travelled=@/360*2pir
=72/360*2*22/77*64
=20275200/2520
=8045.71
=8050km(35.f)

(4ii)
given that speed =800km/hr
distance travelled =804571km
time=distance travelled/speed
=8045.71/800
=10.057
=10hrs(to the nearest hour)

CLICK HERE FOR THE IM AGE NO4

(5i)

MEAN

(X)=EFX/EF=1360/40=34

MODE

L1+[Fm-Fa/2fm-fa-fb]c

=30.5+[12-8/2(12)-8-4]5

=30.5+[4/12]5

=30.5+1.67

=32.17

(5i)

MEAN

(X)=EFX/EF=1360/40=34

MODE

L1+[Fm-Fa/2fm-fa-fb]c

=30.5+[12-8/2(12)-8-4]5

=30.5+[4/12]5

=30.5+1.67

=32.17

CLICK HERE FOR THE IMAGE NO5

==========================

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 6i)

 7+8+x = 47

 15+ 2x =47

 2x = 47- 15

 2x/2 = 32/2
 divide both side by 2

 x=16
 6ii)

 tran only;:

 7+8 + 3 + y=30

 18 +y =30

 y=30 -18 =12 

 :. Tran only =12
 iii) at least two: 7+ 16+ 3 +8 =34
 iv)16 + 7 +12 +16 +8 + 3 + Q=95

 62+ Q =95

 Q= 95 -62

 Q=33 :. Car only = 33
 =========================

(7a)

a+2d=11 —-eq (1)

-(a+8d)=29 —-eq (2)

-6d/-6d = -18/-6

d=3

sub for d=3 in —-eq (1)

a+2(3)=11

a+6=11

a=11-6=5

(7b)

L = ar^n-1

729/3 = 3/3 x 3^n-1

243 = 3^n-1

3^5 = 3^-1

5 = n-1

N = 5+1

= 6

Sn = a(r^-1)/r-1 = 3(3^6 – 1)/3-1

Sn = 3( 729 -1)/2

S6 = 3 x 728/2

S6 = 1092

(7c)

3x^3/3 + x | 2,1

(2^3 + 2) – (1^3+1)

(8+2) – (1+1)

= 8

SOLVING AND TYPING…

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